Chemistry 9701 · AS & A Level · Analytical techniques

Analytical techniques — practice question

A $0.50\,\text{g}$ portion of a Group 2 metal, $M$, was placed into $40.0\,\text{cm}^3$ of $1.00\,\text{mol dm}^{-3}$ hydrochloric acid, which was in excess. Equation 1: $M(s) + 2\text{HCl}(aq) \rightarrow M\text{Cl}_2(aq) + \text{H}_2(g)$
(a)[1]

Find the number of moles of hydrochloric acid in $40.0\,\text{cm}^3$ of $1.00\,\text{mol dm}^{-3}\,\text{HCl$.

(b)

Once the reaction was complete, the mixture was transferred to a volumetric flask and diluted to $100\,\text{cm}^3$. A $10.0\,\text{cm}^3$ aliquot taken from the flask needed $15.0\,\text{cm}^3$ of $0.050\,\text{mol dm}^{-3}$ sodium carbonate solution, $\text{Na}_2\text{CO}_3$, for all of the remaining hydrochloric acid to be neutralised.

(b(i))[1]

Write the equation for the full reaction between sodium carbonate and hydrochloric acid.

(b(ii))[1]

Calculate the amount, in moles, of sodium carbonate required to react with the hydrochloric acid in the $10.0\,\text{cm}^3$ sample from the volumetric flask.

(b(iii))[1]

Calculate the amount, in moles, of hydrochloric acid contained in the $10.0\,\text{cm}^3$ sample.

(b(iv))[1]

Calculate the total amount, in moles, of hydrochloric acid left after the reaction shown in equation 1.

(b(v))[1]

Use your answers to (a) and (b)(iv) to calculate the amount, in moles, of hydrochloric acid that reacted with the $0.50\,\text{g}$ sample of $M$.

(b(vi))[1]

Use your answer to (v) and equation 1 to calculate the amount, in moles, of $M$ in the $0.50\,\text{g}$ sample.

(b(vii))[2]

Calculate the relative atomic mass, $A_r$, of $M$ and identify $M$.

Worked solution & mark scheme

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