A plant cell was put into pure water during an investigation. At the start, the rate at which water molecules moved into the cell, $R$, was higher than the initial rate at which water molecules moved out of the cell. In a separate investigation, a plant cell of the same type was placed in a solution whose water potential was the same as that of the cell contents. What will happen in the second investigation over a period of five minutes?
- AWater molecules will not enter or leave the cell because the water potential of the cell contents is equal to that of the solution.
- BWater molecules will enter and leave the cell in equal amounts, both at an initial rate that is less than $R$ in the first investigation.
- CWater molecules will enter and leave the cell in equal amounts, both at an initial rate that is greater than $R$ in the first investigation.
- DWater molecules will enter and leave the cell in equal amounts, both at an initial rate that is equal to $R$ in the first investigation.