Biology 9700 · AS & A Level · Carbohydrates and lipids

Carbohydrates and lipids — practice question

Fig. 4.1 shows a computer-generated image of the enzyme hexokinase binding to glucose. The product of the enzyme-catalysed reaction is glucose-6-phosphate.
(a)[3]

Hexokinase binds glucose by the induced fit mechanism. Describe how an enzyme-substrate complex forms by this mechanism.

(b)[2]

Suggest how enzymes that use the induced fit mechanism can be less affected by competitive inhibitors than those that use the lock and key mechanism.

(c)[3]

When a solution of the enzyme hexokinase is heated to $45^\circ\text{C}$ for $10$ minutes, the amount of product formed falls by $50\%$ compared with a sample maintained between $30^\circ\text{C}$ and $40^\circ\text{C}$. Explain this result.

(d(i))[2]

State two differences between active transport and facilitated diffusion.

(d(ii))[2]

Suggest why glucose-6-phosphate cannot move out of cells.

Worked solution & mark scheme

This 12-mark question has a full step-by-step worked solution and mark scheme. One marking point: Initially, the substrate is not fully complementary to the active site

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